[Leetcode]_7 Reverse Integer
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注意值范围
然后,就没了。
/** * Index: 7 * Title: Reverse Integer * Author: ltree98 **/class Solution {public: int reverse(int x) { long long ans = 0; while( x != 0 ) { int temp = x % 10; ans = ans*10 + temp; x /= 10; } if(ans > INT_MAX || ans < INT_MIN) return 0; return int(ans); }};
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