类型组合

#include <iostream>struct antarctica_years_end{    int year;};int main(){    antarctica_years_end s01,s02,s03;    s01.year=1998;    antarctica_years_end* pa=&s02;    pa->year=1999;    antarctica_years_end trio[3];    trio[0].year=2003;    std::cout<<trio->year<<std::endl;    const antarctica_years_end * arp[3]={&s01,&s02,&s03};    std::cout<<arp[1]->year<<std::endl;    const antarctica_years_end **ppa=arp;    auto ppb=arp;//c++11 automatic type deduction    //or else use const antarctica_years_end **ppb=arp;    std::cout<<(*ppa)->year<<std::endl;    std::cout<<(*(ppb+1))->year<<std::endl;    return 0;}

这段代码没有 using namespace std;这一句，在输出的时候使用std::cout。

codeblocks可能出现不适配C++11的情况，稍微设置一下就好了。