102.Binary Tree Level Order Traversal
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/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public: vector<vector<int>> levelOrder(TreeNode* root) { vector<vector<int>> v; vector<int> level; TreeNode *temp; queue<TreeNode *> q; if (root) q.push(root); while (!q.empty()) { int len = q.size(); for (int i = 0; i < len; i++) { temp = q.front(); level.push_back(temp->val); if (temp->left)q.push(temp->left); if (temp->right)q.push(temp->right); q.pop(); } v.push_back(level); level.clear(); } return v; }};
利用队列的先进先出的特点,
将每层所有结点的左右子结点按顺序分别入队,
用len记录每层的结点个数,用来控制for循环,
每个for循环遍历当前层所有结点,并保证了能将每一个结点的子节点按顺序入队。
每层遍历结束后清空vector。
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