1012



Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

Sample Output

n e- -----------0 11 22 2.53 2.6666666674 2.708333333
#include <iostream>#include <iomanip>using namespace std;int main(){    cout<<"n"<<" "<<"e"<<endl;    cout<<"- -----------"<<endl;    cout<<"0 1"<<endl;    cout<<"1 2"<<endl;    cout<<"2 2.5"<<endl;    double a=2,b=2.5;    for(int i=3;i<=4;i++)    {        cout<<i<<" ";        a*=i;        cout<<setiosflags(ios::fixed)<<setprecision(9)<<(b+=1/a)<<endl;    }    return 0;}


#include <iostream>using namespace std;int main(){    cout<<"n"<<" "<<"e"<<endl;    cout<<"- -----------"<<endl;    cout<<"0 1"<<endl;    cout<<"1 2"<<endl;    cout<<"2 2.5"<<endl;    cout<<"3 2.666666667"<<endl;    cout<<"4 2.708333333"<<endl;    cout<<"5 2.716666667"<<endl;    cout<<"6 2.718055556"<<endl;    cout<<"7 2.718253968"<<endl;    cout<<"8 2.718278770"<<endl;    cout<<"9 2.718281526"<<endl;    return 0;}