poj 3349 Snowflake Snow Snowflakes（hash）

题目链接：http://poj.org/problem?id=3349

Snowflake Snow Snowflakes

Time Limit: 4000MS Memory Limit: 65536KTotal Submissions: 40754 Accepted: 10734

Description

You may have heard that no two snowflakes are alike. Your task is to write a program to determine whether this is really true. Your program will read information about a collection of snowflakes, and search for a pair that may be identical. Each snowflake has six arms. For each snowflake, your program will be provided with a measurement of the length of each of the six arms. Any pair of snowflakes which have the same lengths of corresponding arms should be flagged by your program as possibly identical.

Input

The first line of input will contain a single integer n, 0 < n ≤ 100000, the number of snowflakes to follow. This will be followed by n lines, each describing a snowflake. Each snowflake will be described by a line containing six integers (each integer is at least 0 and less than 10000000), the lengths of the arms of the snow ake. The lengths of the arms will be given in order around the snowflake (either clockwise or counterclockwise), but they may begin with any of the six arms. For example, the same snowflake could be described as 1 2 3 4 5 6 or 4 3 2 1 6 5.

Output

If all of the snowflakes are distinct, your program should print the message:
No two snowflakes are alike.
If there is a pair of possibly identical snow akes, your program should print the message:
Twin snowflakes found.

Sample Input

21 2 3 4 5 64 3 2 1 6 5

Sample Output

Twin snowflakes found.

Source

CCC 2007

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题意：给你两朵雪花，问这两朵雪花通过旋转，是否一样

解析：hash一下，这朵雪花的六个瓣的和，就是 mod 100007，然雪花旋转比较下就可以了

代码：

#include<iostream>#include<algorithm>#include<cstdio>#include<cstring>#include<cmath>#include<vector>#include<stack>#include<queue>#define N 100009using namespace std;const int INF = 0x3f3f3f3f;const int mod = 1e5 + 7;vector<int> h[N];int snow[N][7], sum[N];bool check(int a, int b){    for(int i = 0; i < 6; i++)    {        if(snow[a][0] == snow[b][i%6])        {            if(snow[a][1] == snow[b][(i+1)%6] && snow[a][2] == snow[b][(i+2)%6] && snow[a][3] == snow[b][(i+3)%6] && snow[a][4] == snow[b][(i+4)%6] && snow[a][5] == snow[b][(i+5)%6])                return true;        }        if(snow[a][5] == snow[b][i%6])        {            if(snow[a][4] == snow[b][(i+1)%6] && snow[a][3] == snow[b][(i+2)%6] && snow[a][2] == snow[b][(i+3)%6] && snow[a][1] == snow[b][(i+4)%6] && snow[a][0] == snow[b][(i+5)%6])                return true;        }    }    return false;}int main(){    int n, f = 0;    scanf("%d", &n);    memset(sum, 0, sizeof(sum));    for(int i = 0; i < n; i++) h[i].clear();    for(int i = 0; i < n; i++)    {        sum[i] = 0;        for(int j = 0; j < 6; j++)        {            scanf("%d", &snow[i][j]);            sum[i] += snow[i][j];        }    }    for(int i = 0; i < n; i++)    {        int key = sum[i] % mod;        for(int j = 0; j < h[key].size(); j++)        {            if(check(i, h[key][j])) f = 1;            if(f) break;        }        if(f) break;        h[key].push_back(i);    }    if(f) puts("Twin snowflakes found.");    else puts("No two snowflakes are alike.");    return 0;}