LeetCode 136 Single Number
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Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
AC代码如下：（位运算的经典应用）
class Solution {public: int singleNumber(vector<int>& nums) { int ret=0; for(int i=0;i<nums.size();i++) ret^=nums[i]; return ret; }}; 0 0
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