LeetCode 231 Power of Two

Given an integer, write a function to determine if it is a power of two.

AC代码如下：

class Solution {public:    bool isPowerOfTwo(int n) {        if(n<=0)            return false;        int count=0;        for(int i=0;i<sizeof(int)*8;i++){            if(n>>i&1==1)                count++;            if(count>=2)                return false;        }        return true;    }};

看了大牛的解答，后自愧不如，代码如下：

class Solution {public:    bool isPowerOfTwo(int n) {        return n > 0 && !(n&(n-1));    }};