JAVA学习笔记_判断二位数组是否存在连续4个数的值相同

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public class ConsecutiveFour {public static void main(String[] args) {int[][] arr={{0,1,0,6,1,6,1},  {0,1,6,8,3,0,1},  {5,8,4,6,8,6,9},  {6,5,4,8,1,9,7},  {1,3,7,4,4,4,6},  {3,3,2,5,4,0,7},  {1,2,3,3,5,9,7}};System.out.println(ConsecutiveFour.isConsecutiveFour(arr));} public static boolean isConsecutiveFour(int[][] values) {    for (int x = 0; x < values.length; x++) {      for (int y = 0; y < values[x].length; y++) {        if (y >= 3 && equals(values[x][y], values[x][y - 1], values[x][y - 2], values[x][y - 3])) {          return true;        }        if (x >= 3 && equals(values[x][y], values[x - 1][y], values[x - 2][y], values[x - 3][y])) {          return true;        }        if (x >= 3 && y >= 3 && equals(values[x][y], values[x - 1][y - 1], values[x - 2][y - 2], values[x - 3][y - 3])) {          return true;        }        if (x < values.length-3 && y >= 3 && equals(values[x][y], values[x +1][y - 1], values[x + 2][y - 2], values[x + 3][y - 3])) {          return true;        }      }    }    return false;  }  private static boolean equals(int... arr) {    for (int i = 0; i < arr.length - 1; i++) {      if (arr[i] != arr[i + 1]) {        return false;      }    }    return true;  }}

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