UVA
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#include<bits/stdc++.h>using namespace std;const int maxn = 40000;int a[maxn],b[maxn];int sss(int t, int n){ int sum = 1,tt; for(int i = 0; i < n; i++) { tt = 1; if(t%b[i] == 0) while(t % b[i] == 0) { t /= b[i]; tt++; } sum *= tt; } return sum;}int main(){ fill(a, a + maxn, 1); for(int i = 2;i <= 20000; i++) { for(int j = 2*i ; j <= maxn; j += i) a[j] = 0; } int count_n = 0; for(int i = 2; i<= maxn; i++) if(a[i]) b[count_n++] = i; int t ; cin >> t; while(t--) { int p, q; cin >> p >> q; int sum = 0, chucun = 0;; for(int i = p; i <= q; i++) { int w = sss(i, count_n); if(sum < w) { sum = w; chucun = i; } } printf("Between %d and %d, %d has a maximum of %d divisors.\n",p, q,chucun ,sum); } return 0;}
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