10763--Foreign Exchange--Uva
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1.第一反应是用map,结果Wrong Answer,检查漏了花括号,加上之后依然Wrong Answer
2.数据会有重复的,不能用map,::>_<::,改用multimap,遍历比较,忽略了相同key,不同value的排序问题
3.不再考虑排序,找到一个,剔除一个,避免重复查找,Accepted
思路:
用两个multimap A、B,正序反序分别存入,如果可行两者完全相等(不考虑顺序),遍历A,在B中找完全相同的元素并erase掉,找不到直接退出遍历
代码:
#include<map>#include<stdio.h>#include<iterator>#include<iostream>using namespace std;multimap<int,int> students1,students2;multimap<int,int>::iterator itr1;multimap<int,int>::iterator itr2;int main() { int n,original,target; while(cin >> n) { if (n == 0) { break; } bool ans = true ; bool flag = false ; students1.clear(); students2.clear(); for(int i = 0; i < n; i++) { cin >> original >> target; students1.insert(make_pair(original,target)); students2.insert(make_pair(target,original)); } for(itr1 = students1.begin(); itr1 != students1.end(); itr1++) { flag = false; for(itr2 = students2.find(itr1->first); itr2 != students2.end(); itr2++) { if(itr1->second == itr2->second) { students2.erase(itr2); flag = true; break; } } if(flag == false) { ans = false; break; } } printf("%s\n",ans ? "YES":"NO"); } return 0;}
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