Tell me the area(计算几何--求两圆相交面积)

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Problem Link:http://acm.hdu.edu.cn/showproblem.php?pid=1798


Tell me the area

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 2828    Accepted Submission(s): 903


Problem Description
    There are two circles in the plane (shown in the below picture), there is a common area between the two circles. The problem is easy that you just tell me the common area.

 

Input
There are many cases. In each case, there are two lines. Each line has three numbers: the coordinates (X and Y) of the centre of a circle, and the radius of the circle.
 

Output
For each case, you just print the common area which is rounded to three digits after the decimal point. For more details, just look at the sample.
 

Sample Input
0 0 22 2 1
 

Sample Output
0.108
 

Author
wangye
 

Source
2008 “Insigma International Cup” Zhejiang Collegiate Programming Contest - Warm Up(4)


AC code:

#include<stdio.h>#include<math.h>#include<string.h>#include<algorithm>#define PI acos(-1)using namespace std;int main(){int T;double r1,r2,x1,x2,y1,y2,dr,r,A1,A2,p,s,s1,s2,ans;while(scanf("%lf%lf%lf",&x1,&y1,&r1)!=EOF){scanf("%lf%lf%lf",&x2,&y2,&r2);dr=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));r=min(r1,r2);if(dr>=r1+r2)printf("0.000\n");else if(dr<=fabs(r1-r2) && dr>=0){ans=PI*r*r;printf("%0.3lf\n",ans);}else{A1=acos((r1*r1+dr*dr-r2*r2)/(2*r1*dr));A2=acos((r2*r2+dr*dr-r1*r1)/(2*r2*dr));p=(r1+r2+dr)/2;s=sqrt(p*(p-r1)*(p-r2)*(p-dr));s1=s-PI*r2*r2*(A2/(2*PI));s2=s-PI*r1*r1*(A1/(2*PI));ans=2*(s-s1-s2);printf("%.3lf\n",ans);}}return 0;}


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