ZOJ3782-Ternary Calculation

来源:互联网 发布:爱知女性绑架杀害事件 编辑:程序博客网 时间:2024/04/29 13:42

Ternary Calculation

Time Limit: 2 Seconds      Memory Limit: 65536 KB

Complete the ternary calculation.

Input

There are multiple test cases. The first line of input contains an integer T indicating the number of test cases. For each test case:

There is a string in the form of "number1 operatora number2 operatorb number3". Each operator will be one of {'+', '-' , '*', '/', '%'}, and each number will be an integer in [1, 1000].

Output

For each test case, output the answer.

Sample Input

51 + 2 * 31 - 8 / 31 + 2 - 37 * 8 / 55 - 8 % 3

Sample Output

7-10113

Note

The calculation "A % B" means taking the remainder of A divided by B, and "A / B" means taking the quotient.


Author: ZHOU, Yuchen
Source: The 11th Zhejiang Provincial Collegiate Programming Contest


题意:给你一串算式,计算出答案


#include <iostream>#include <cstdio>#include <algorithm>#include <cmath>#include <cstring>#include <string>#include <map>#include <vector>#include <queue>#include <bitset>#include <stack>using namespace std;int main(){    char ch1,ch2;    int a,b,c;    int t;    scanf("%d",&t);    while(t--)    {        scanf("%d %c %d %c %d",&a,&ch1,&b,&ch2,&c);        if(ch1=='+'||ch1=='-')        {            int ans;            if(ch2=='+') ans=b+c;            else if(ch2=='-') ans=b-c;            else if(ch2=='*') ans=b*c;            else if(ch2=='/') ans=b/c;            else ans=b%c;            if(ch1=='+') printf("%d\n",ans+a);            else            {                if(ch2=='-') printf("%d\n",a-b-c);                else if(ch2=='+') printf("%d\n",a-b+c);                else printf("%d\n",a-ans);            }        }        else        {            int ans;            if(ch1=='*') ans=a*b;            else if(ch1=='/') ans=a/b;            else if(ch1=='%') ans=a%b;            if(ch2=='+') printf("%d\n",ans+c);            else if(ch2=='-') printf("%d\n",ans-c);            else if(ch2=='*') printf("%d\n",ans*c);            else if(ch2=='/') printf("%d\n",ans/c);            else printf("%d\n",ans%c);        }    }    return 0;}

0 0
原创粉丝点击