A. Display Size

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

A big company decided to launch a new series of rectangular displays, and decided that the display must have exactly n pixels.

Your task is to determine the size of the rectangular display — the number of lines (rows) of pixels a and the number of columns of pixels b, so that:

• there are exactly n pixels on the display;
• the number of rows does not exceed the number of columns, it means a ≤ b;
• the difference b - a is as small as possible.

Input

The first line contains the positive integer n (1 ≤ n ≤ 106) — the number of pixels display should have.

Output

Print two integers — the number of rows and columns on the display.

Examples

input

8

output

2 4

input

64

output

8 8

input

5

output

1 5

input

999999

output

999 1001

Note

In the first example the minimum possible difference equals 2, so on the display should be 2 rows of 4 pixels.

In the second example the minimum possible difference equals 0, so on the display should be 8 rows of 8 pixels.

In the third example the minimum possible difference equals 4, so on the display should be 1 row of 5 pixels.

解题说明：此题的意思其实就是将一个数拆分为两个数的乘积。同时要求两个数尽可能接近。可以采用暴力方法，首先从这个数的平方根最接近的整数开始，一个往上，一个往下，找到乘积正好为该数的两个数。

#include<cstdio>#include<algorithm>#include<cstring>#include<cstdlib>#include<iostream>using namespace std;int main(){int n,a,b,i;scanf("%d",&n);for(i=1;i*i<=n;i++){if(n%i==0){a=i;b=n/i;}}printf("%d %d\n",a,b);}