LeetCode 100. Same Tree
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Given two binary trees, write a function to check if they are equal or not.
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
public class Solution { public boolean isSameTree(TreeNode p, TreeNode q) { //非循环实现 /*if(p==null && q==null){ //两棵空树 return true; } else if(p==null || q==null){ //一棵空树,一棵非空树 return false; } else{ //两棵非空树 Stack<TreeNode> s1=new Stack<TreeNode>(); Stack<TreeNode> s2=new Stack<TreeNode>(); s1.push(p); s2.push(q); try{ while(s1!=null && s2!=null){ TreeNode ps=s1.pop(); TreeNode qs=s2.pop(); if(ps.val!=qs.val){ return false; }else{ if(ps.left!=null && qs.left!=null){ //左子树同时不为空 s1.push(ps.left); s2.push(qs.left); }else if(ps.left!=null || qs.left!=null){ //左子树不同时为空 return false; } if(ps.right!=null && qs.right!=null){ //右子树同时为空 s1.push(ps.right); s2.push(qs.right); }else if(ps.right!=null || qs.right!=null){ //右子树不同时为空 return false; } } } if(s1==null && s2==null){ //两棵树的节点一样多 return true; }else{ return false; } }catch(Exception e){ } return true; }*/ //循环实现 if(p==null && q==null){ return true; } else if(p==null || q==null){ return false; } else{ if(p.val==q.val){ return (isSameTree(p.left,q.left)&& isSameTree(p.right,q.right)); }else{ return false; } } }}
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