比较两个数二进制序列有几位不同

两个int（32位）整数m和n的二进制表达中，有多少个位(bit)不同？ 
输入例子:
1999 2299
输出例子:7

#define _CRT_SECURE_NO_WARNINGS 1#include <stdio.h>#include <windows.h>int main(){int arr1[32] = { 0 };int arr2[32] = { 0 };int num1 = 0; int num2 = 0;printf("请输入两个数:");scanf("%d %d", &num1, &num2);int i = 0;for (i = 31; i >= 0; i--){arr1[i] = (num1 >> i) & 1;}for (i = 31; i >= 0; i--){arr2[i] = (num2 >> i) & 1;}int count = 0;for (i = 31; i >= 0; i--){if (arr1[i] != arr2[i]){count++;}}printf("%d的二进制序列为：\n", num1);for (i = 31; i >= 0; i--){printf("%d", arr1[i]);}printf("\n");printf("%d的二进制序列为：\n", num2);for (i = 31; i >= 0; i--){printf("%d", arr2[i]);}printf("\n");printf("%d和%d二进制序列中有%d位不同\n", num1, num2, count);system("pause");return 0;}