HDU-1004Let the Balloon Rise

Let the Balloon Rise

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 118510    Accepted Submission(s): 46446

Problem Description

Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.

This year, they decide to leave this lovely job to you. 

 

Input

Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.

A test case with N = 0 terminates the input and this test case is not to be processed.

 

Output

For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.

 

Sample Input

5greenredblueredred3pinkorangepink0

 

Sample Output 

redpink

解题思路：将每次输入的第一个颜色单独去出来 作为比较的对象，然后另设一个存储数组，用来保存出现的次数。

解题代码：

package First;import java.util.Scanner;public class Problem1004 {public static void main(String[] args) {Scanner sc = new Scanner(System.in); while(sc.hasNext()){ int n = sc.nextInt(); if(n==0){  System.exit(0);//关闭当前进程。 } String[] str = new String[1000]; int[] number = new int[1000]; number[0]=0; str[0]=sc.next(); for(int i=1;i<n;i++){ str[i] = sc.next(); number[i]=0; for(int j=0;j<i-1;j++){ if(str[i].equals(str[j])){ number[i]++; } } }  int max=number[0],a=0; for(int i=1;i<n;i++){ if(number[i]>max){ max=number[i]; a=i; } } System.out.println(str[a]); }}}