[kuangbin带你飞]专题一 简单搜索 -E

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Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.

Input
The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.

Output
For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.

Sample Input
2
6
19
0

Sample Output
10
100100100100100100
111111111111111111

无符号长整才能过,怎么能这样

#include"iostream"using namespace std;typedef unsigned long long ll;int n;bool sign;void dfs(ll x,int cur){    if(sign)    return ;    if(x%n==0)    {        cout<<x<<endl;        sign=true;        return;    }    if(cur==19)    return;    dfs(x*10,cur+1);    dfs(x*10+1,cur+1);}int main(){    while(cin>>n&&n)    {        sign=false;        dfs(1,0);    }    return 0;}
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