题目1038：Sum of Factorials

题目1038：Sum of Factorials

时间限制：1 秒

内存限制：32 兆

特殊判题：否

提交：2460

解决：1049

题目描述：

    John von Neumann, b. Dec. 28, 1903, d. Feb. 8, 1957, was a Hungarian-American mathematician who made important contributions to the foundations of mathematics, logic, quantum physics, meteorology, science, computers, and game theory. He was noted for a phenomenal memory and the speed with which he absorbed ideas and solved problems. In 1925 he received a B.S. diploma in chemical engineering from Zurich Institute and in 1926 a Ph.D. in mathematics from the University of Budapest, His Ph.D. dissertation on set theory was an important contributions to the subject.
    At the age of 20, von Neumann proposed a new definition of ordinal numbers that was universally adopted. While still in his twenties, he made many contributions in both pure and applied mathematics that established him as a mathematician of unusual depth. His Mathematical Foundation of Quantum Mechanics (1932) built a solid framework for the new scientific discipline.
    During this time he also proved the mini-max theorem of GAME THEORY. He gradually expanded his work in game theory, and with coauthor Oskar Morgenstern he wrote Theory of Games and Economic Behavior (1944).
    There are some numbers which can be expressed by the sum of factorials. For example 9, 9 = 1! + 2! + 3! . Dr. von Neumann was very interested in such numbers. So, he gives you a number n, and wants you to tell whether or not the number can be expressed by the sum of some factorials.
Well, it is just a piece of case. For a given n, you will check if there are some xi, and let n equal to Σt (上标) i=1（下标） xi! (t≥1, xi≥0, xi = xj <==> i = j)
           t
     即 Σ  xi! (t≥1, xi≥0, xi = xj <==> i = j)
          i=1
    If the answer is yes, say "YES"; otherwise, print out "NO".

输入：

    You will get a non-negative integer n (n≤1,000,000) from input file.

输出：

    For the n in the input file, you should print exactly one word ("YES" or "NO") in a single line. No extra spaces are allowed.

样例输入：

92

样例输出：

YESYES

来源：

2007年上海交通大学计算机研究生机试真题

答疑：

解题遇到问题?分享解题心得?讨论本题请访问：http://t.jobdu.com/thread-7762-1-1.html

思路:因为这里n<=1000000,所以10！=3628800已经足够了，而且这里要注意下就是0！=1，这个不能忽略；把输入的数从大到小依次减去对应的结成数数值，判断是否为0即可。

#include<iostream>#include<fstream>using namespace std;int sum[11];int main(){    ifstream in;    in.open("1.txt");    sum[0]=1;    for(int i=1;i<11;++i)        sum[i]=sum[i-1]*i;        int n;    while(cin>>n)    {        if(n==0)            cout<<"NO"<<endl;        else        {            for(int i=10;i>=0;--i)            {                if(n>=sum[i])                    n=n-sum[i];            }            if(n==0)                cout<<"YES"<<endl;            else cout<<"NO"<<endl;        }    }    return 0;}