165. Compare Version Numbers

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

Credits:
Special thanks to @ts for adding this problem and creating all test cases.

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public class Solution {    public int compareVersion(String version1, String version2) {        String[] d1 = version1.split("\\.");String[] d2 = version2.split("\\.");int i = 0;while (i < d1.length && i < d2.length) {int n1 = Integer.parseInt(d1[i]);int n2 = Integer.parseInt(d2[i]);if (n1 > n2)return 1;else if (n1 < n2)return -1;elsei++;}if (i == d1.length && i == d2.length)return 0;else if (i == d1.length) {while (i < d2.length) {if (Integer.parseInt(d2[i]) != 0)return -1;i++;}return 0;} else {while (i < d1.length) {if (Integer.parseInt(d1[i]) != 0)return 1;i++;}return 0;}    }}