[LeetCode]122. Best Time to Buy and Sell Stock II
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[LeetCode]122. Best Time to Buy and Sell Stock II
题目描述
思路
I的后续
将数组分为几个小部分,
划分标准是 [i] < [i - 1](划分原因可以给出数学解释,较简单)
之后每个部分使用之前的思路即可
参考 [LeetCode]121. Best Time to Buy and Sell Stock
代码
#include <iostream>#include <vector>#include <algorithm>using namespace std;class Solution {public: int maxProfit(vector<int>& prices) { int maxCur = 0, maxAll = 0, res = 0; for (int i = 1; i < prices.size(); ++i) { maxCur = max(0, maxCur += prices[i] - prices[i - 1]); maxAll = max(maxCur, maxAll); if (prices[i] - prices[i - 1] < 0 || i == prices.size() - 1) { res += maxAll; maxAll = 0; maxCur = 0; } } return res; }};int main() { vector<int> prices = { 3,2,6,5,0,3 }; Solution s; cout << s.maxProfit(prices) << endl; system("pause"); return 0;}
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