1002 A + B Problem II

#include<iostream>#include<string>using namespace std;/* 一定不要这么写，因为没有把值传回去void max_L(string a, string b){string c;if (a.length() < b.length()){c = a;a = b;b = c;}}*/int main(){    int test, a_L, b_L,sum[10000];//测试次数，a,b的位数减一，和    int num = 0;//进位    string a, b;//a,b    int num1, num2;//化成整型的每一位数    cin >> test;    if (test >= 1 && test <= 20)    {        for (int i = 0; i < test; i++)        {            cin >> a >> b;              cout << "Case " << i + 1 << ":" << endl;//C大写            cout << a << " + " << b << " = " ;            //max_L(a, b);            if (a.length() < b.length())            {                string c;                c = a;                a = b;                b = c;            }            a_L = a.length()-1;            b_L = b.length()-1;            int sum_L;            for (sum_L = 0; sum_L <= b_L; sum_L++)            {                num1 = a[a_L-sum_L] - '0';//一定要转成数字，不然是字符,计算的第一个数应该是数组的最后一个                num2 = b[b_L-sum_L] - '0';//一定要转成数字，不然是字符                sum[sum_L] = (num1 + num2 + num) % 10;//sum是整型数组                num = (num1 + num2 + num) / 10;            }            for (sum_L = (b_L+1); sum_L <= a_L; sum_L++)            {                num1 = a[a_L-sum_L] - '0';//一定要转成数字，不然是字符                sum[sum_L] = (num1 + num) % 10;                num = (num1 + num) / 10;            }            sum_L--;//循环完成多加了一个1，一定要减掉            if (num != 0)            {                sum_L++;//别忘了会多一位                sum[sum_L] = num;            }            num = 0;//本次循环完成一定要清零，否则下次循环还会用            for (int j = 0; j <= sum_L; j++)            {                cout << sum[sum_L - j];                         }            cout << endl;            if (i < (test - 1))            {                cout << endl; //最后一行不空行            }        }    }    return 0;}