题目1138：进制转换

来源：互联网发布：c语言病毒编辑：程序博客网时间：2024/05/24 04:11
#include <stdio.h>  #include <string.h>  #include <stdlib.h>      #define DATA 40  #define MAX 200      void tenToBin(char *str);      char bin[MAX];      int main()  {      char str[DATA];          while(scanf("%s", str) != EOF)      {          tenToBin(str);          puts(bin);        }          return 0;  }      /**  * Description:字符串整数转换为二进制  */ void tenToBin(char *str)  {      int i, j, k, len, sum, d;      char temp;          //初始化参数      sum = 1;      len = strlen(str);      k = 0;      memset(bin, 0, sizeof(bin));          while(sum)      {          sum = 0;              for(i = 0; i < len; i ++)          {              d = (str[i] - '0') / 2;              sum += d;                  if(i == len - 1)              {                  bin[k ++] = (str[i] - '0') % 2 + '0';              }else             {                  str[i + 1] += (str[i] - '0') % 2 * 10;              }                  str[i] = d + '0';          }      }              //逆序      for(i = 0, j = k - 1; i < j; i ++, j --)      {          temp = bin[j];          bin[j] = bin[i];          bin[i] = temp;      }  }  /**************************************************************    Problem: 1138    User: Leeeeo    Language: C++    Result: Accepted    Time:120 ms    Memory:1020 kb****************************************************************/
0 0