Problem B: 一切皆对象

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Problem B: 一切皆对象

Time Limit: 1 Sec Memory Limit: 128 MB
Submit: 1487 Solved: 951
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Description

一切都是对象 —— Everything is an object。所以，现在定义一个类Thing，来描述世界上所有有名字的事物。该类只有构造函数、拷贝构造函数和析构函数，并具有一个字符串数据成员来存储其名字。

Input

输入只有1行，是一个没有空白符的字符串。

Output

见样例。

Sample Input

NAME

Sample Output

A thing without name is created!A thing without name is copied!A thing named by NAME is created!A thing named by NAME is copied!A thing named by NAME is erased!A thing named by NAME is erased!A thing without name is erased!A thing without name is erased!

HINT

Append Code

append.cc,

#include <iostream>#include <string>using namespace std;class Thing{public:    string name;    Thing():name("without name"){cout<<"A thing without name is created!"<<endl;}    Thing(string name):name(name){cout<<"A thing named by "<<name<<" is created!"<<endl;}    Thing(const Thing &t)    {name = t.name;    if(name == "without name")    cout<<"A thing "<<name<<" is copied!"<<endl;   else  cout<<"A thing named by "<<name<<" is copied!"<<endl;}    ~Thing(){if(name == "without name") cout<<"A thing "<<name<<" is erased!"<<endl; else cout<<"A thing named by "<<name<<" is erased!"<<endl; }};int main(){    string name;    Thing Thing1, Thing2(Thing1);    cin>>name;    Thing Thing3(name);    Thing Thing4(Thing3);    return 0;}

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