Problem E: 正方形、长方形、立方体

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Problem E: 正方形、长方形、立方体

Time Limit: 3 Sec  Memory Limit: 128 MB
Submit: 1804  Solved: 1273
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Description

给出正方形(Square)、长方形(Rectangle)、立方体(Cuboid)的边长,求周长、面积、体积。
Square类只需存一条边长,构造函数产生一条输出,有边长、周长、面积的函数。
Rectangle类需存长和宽,若从Square类派生而来,因此只需增加一条边,构造函数产生一条输出,有长、宽、周长、面积的函数。
Cuboid类需存长宽高,若从Rectangle类派生而来,因此也只增加一条边,构造函数产生一条输出,有长、宽、高、周长、面积、体积的函数。它的周长定义为所有棱长之和。
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请仔细阅读append.cc代码,并设计好正方形、长方形、立方体派生关系,使main()函数能够运行并得到正确的输出。

Input

输入分为三部分,每一部分都已一个整数n开始,表示后面有n组测试数据。
在第一部分测试数据中,每组是一个整数,表示正方形的边长。
在第二部分测试数据中,每组是两个整数,表示长方形的长和宽。
在第三部分测试数据中,每组是三个整数, 表示立方体的长和宽。

Output

每组测试数据对应的输出为两部分,前面是构造函数的输出,最后是输出图形的信息,包括长宽高、周长、面积、体积等信息,格式见sample;

Sample Input

1413 413 4 6

Sample Output

Construct Square (4)A Square length 4, Perimeter 16, Area 16=========================Construct Square (3)Construct Rectangle (3, 4)A Rectangle length 3, width 4, Perimeter 14, Area 12=========================Construct Square (3)Construct Rectangle (3, 4)Construct Cuboid (3, 4, 6)A Cuboid length 3, width 4, height 6, Perimeter 52, Area 108, Volume 72

HINT

Append Code

append.c, append.cc,
#include <iostream>using namespace std;class Square{public:    int l;    Square(int l=0):l(l){cout<<"Construct Square ("<<l<<")"<<endl;}    int length(){return l;}    int perimeter(){return 4*l;}    int area(){return l*l;}};class Rectangle:public Square{public:    int w;    Rectangle(int _l,int _w):Square(_l)    {        w = _w;        cout<<"Construct Rectangle ("<<l<<", "<<w<<")"<<endl;    }    int width(){return w;}    int perimeter(){return 2*(l+w);}    int area(){return l*w;}};class Cuboid:public Rectangle{public:    int h;    Cuboid(int l,int w,int h):Rectangle(l,w),h(h){cout<<"Construct Cuboid ("<<l<<", "<<w<<", "<<h<<")"<<endl;}    int perimeter(){return 4*(l+w+h);}    int height(){return h;}    int area() {return 2*(l*w+w*h+h*l);}    int volume(){return l*w*h;}};int main(){    int cases, l, w, h;    cin >> cases;    for(int i = 1; i <= cases; ++i)    {        cin >> l;        Square squa(l);        cout << "A Square length " << squa.length() << ", ";        cout << "Perimeter " << squa.perimeter() << ", ";        cout << "Area " << squa.area() << endl;    }    cout << "=========================" << endl;    cin >> cases;    for(int i = 1; i <= cases; ++i)    {        cin >> l >> w;        Rectangle rect(l, w);        cout << "A Rectangle length " << rect.length() << ", width " << rect.width() << ", ";        cout << "Perimeter " << rect.perimeter() << ", ";        cout << "Area " << rect.area() << endl;    }    cout << "=========================" << endl;    cin >> cases;    for(int i = 1; i <= cases; ++i)    {        cin >> l >> w >> h;        Cuboid cubo(l, w, h);        cout << "A Cuboid length " << cubo.length() << ", width " << cubo.width() << ", height " << cubo.height() << ", ";        cout << "Perimeter " << cubo.perimeter() << ", ";        cout << "Area " << cubo.area() << ", ";        cout << "Volume " << cubo.volume() << endl;    }}

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