1028. List Sorting (25)

Excel can sort records according to any column. Now you are supposed to imitate this function.

Input

Each input file contains one test case. For each case, the first line contains two integers N (<=100000) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

Output

For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.

Sample Input 1

3 1000007 James 85000010 Amy 90000001 Zoe 60

Sample Output 1

000001 Zoe 60000007 James 85000010 Amy 90

Sample Input 2

4 2000007 James 85000010 Amy 90000001 Zoe 60000002 James 98

Sample Output 2

000010 Amy 90000002 James 98000007 James 85000001 Zoe 60

Sample Input 3

4 3000007 James 85000010 Amy 90000001 Zoe 60000002 James 90

Sample Output 3

000001 Zoe 60000007 James 85000002 James 90000010 Amy 90

第一次遇到， 用cin cout会超时，需要用scanf printf，网上查了一下是scanf printf是格式化输入效率较高，cin cout是输入输出流，对于大量输入输出应尽量用scanf printf

/***用cin cout会超时***/#include <iostream>#include <string>#include <algorithm>#include <cstdio>#include <cstring>#define MAX 100005using namespace std;struct stu{    char name[15];    int id;    int grade;}s[MAX];bool cmp1(const stu &a, const stu &b){    return a.id < b.id;}bool cmp2(const stu &a, const stu &b){    if(strcmp(a.name, b.name) == 0)        return a.id < b.id;    return strcmp(a.name, b.name) < 0;}bool cmp3(const stu &a, const stu &b){    if(a.grade == b.grade)        return a.id < b.id;    return a.grade <= b.grade;}int main(){    int n, c;    scanf("%d%d", &n, &c);    for(int i=0; i<n; i++)        scanf("%d %s %d", &s[i].id, s[i].name, &s[i].grade);    switch(c)    {        case 1: sort(s, s+n, cmp1);break;        case 2: sort(s, s+n, cmp2);break;        case 3: sort(s, s+n, cmp3);break;    }    for(int i=0; i<n; i++)    {        printf("%06d %s %d\n", s[i].id, s[i].name, s[i].grade);    }    return 0;}