POJ 1002 487-3279 G++
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#include <stdio.h>#include <string.h>#include <stdlib.h>//散列表 int sl[10000000]; int main(){int NUM;scanf("%d ",&NUM);char s[NUM][100];memset(s,0,sizeof(s));int i;for(i=0;i<NUM;i++){scanf("%s",&s[i]);}int j;for(j=0;j<NUM;j++){int taiy=0;for(i=0;i<strlen(s[j]);i++){if(s[j][i]=='-'){continue;}else if(s[j][i]!='-'){if((s[j][i]>='0')&&(s[j][i]<='9')){taiy=taiy*10+s[j][i]-'0';}else if((s[j][i]=='A')||(s[j][i]=='B')||(s[j][i]=='C')){taiy=taiy*10+'2'-'0';}else if((s[j][i]=='D')||(s[j][i]=='E')||(s[j][i]=='F')){taiy=taiy*10+'3'-'0';}else if((s[j][i]=='G')||(s[j][i]=='H')||(s[j][i]=='I')){taiy=taiy*10+'4'-'0';}else if((s[j][i]=='J')||(s[j][i]=='K')||(s[j][i]=='L')){taiy=taiy*10+'5'-'0';}else if((s[j][i]=='M')||(s[j][i]=='N')||(s[j][i]=='O')){taiy=taiy*10+'6'-'0';}else if((s[j][i]=='P')||(s[j][i]=='R')||(s[j][i]=='S')){taiy=taiy*10+'7'-'0';}else if((s[j][i]=='T')||(s[j][i]=='U')||(s[j][i]=='V')){taiy=taiy*10+'8'-'0';}else if((s[j][i]=='W')||(s[j][i]=='X')||(s[j][i]=='Y')){taiy=taiy*10+'9'-'0';}}}//printf("%d\n",taiy);sl[taiy]++;}int flag=0;for(i=0;i<10000000;i++){if(sl[i]>1){printf("%d",i/1000000);printf("%d",(i/100000)%10);printf("%d",(i/10000)%10);printf("-");printf("%d",(i/1000)%10);printf("%d",(i/100)%10);printf("%d",(i/10)%10);printf("%d",i%10);printf(" %d\n",sl[i]);flag=1;}}if(flag==0){printf( "No duplicates.\n" );//谢谢赵瑞阳老师 }return 0;}
把包括字母的电话号码翻译成数字。按字母序输出出现大于2次的电话号码。如果没有号码重复输出“No duplicates. ”。
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