2. Add Two Numbers
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题目:
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
ListNode 在这里的构造函数是需要传入值的
操作的时候需要注意!!!:定义了head之后不要对head直接操作,要ListNode node = head;这样起别名,这样head永远是head,而剩下来的操作是对node来进行的。比如node = node.next;
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */public class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode head = new ListNode(0); ListNode l3 = head; int carry = 0; while(l1!=null||l2!=null||carry!=0){ if(l1==null) l1 = new ListNode(0); if(l2==null) l2 = new ListNode(0); int i = l1.val+l2.val+carry; if(i>=10){ i=i-10; carry=1; }else{ carry = 0; } l3.next = new ListNode(i);//因为l3是新创建的,所以每次加完就要创建一个新的next node并且赋值为i l3 = l3.next; l1 = l1.next; l2 = l2.next; } return head.next; }}
0 0
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- 2. Add Two Numbers
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