A(1886): Phone List

Description

　　Given a list of phone numbers, determine if it is consistent in the sense that no number is the prefix of another. Let’s say the phone catalogue listed these numbers:

• Emergency 911
• Alice 97 625 999
• Bob 91 12 54 26

　　In this case, it’s not possible to call Bob, because the central would direct your call to the emergency line as soon as you had dialled the first three digits of Bob’s phone number. So this list would not be consistent.

Input

The first line of input gives a single integer, 1<=t<=40, the number of test cases. Each test case starts with n, the number of phone numbers, on a separate line, 1<=n<=10000. Then follows n lines with one unique phone number on each line. A phone number is a sequence of at most ten digits.

Output

For each test case, output “YES” if the list is consistent, or “NO” otherwise.

Sample Input

2391197625999911254265113123401234401234598346

Sample Output

NOYES

Hint

题意：找是否存在一个号码是另一个号码的前缀。

思路：将所有号码进行排序，每个号码只需要跟它后面一个号码进行比较就行了（之前就有看过这题的题解）。

#include<iostream>#include<string.h>#include<algorithm>using namespace std;char a[10005][11];int cmp(const void *m,const void *n){return strcmp((char*)m,(char*)n);}int main(){int t;cin>>t;while(t--){int n;cin>>n;for(int i=0;i<n;i++) cin>>a[i];    qsort(a,n,sizeof(a[0]),cmp);bool flag=1;for(int i=0;i<n-1&&flag;i++){if(strncmp(a[i],a[i+1],strlen(a[i]))==0) flag=0;}if(flag) cout<<"YES";else     cout<<"NO";cout<<endl;}}