HDU1005 Number Sequence
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Problem Description
A number sequence is defined as follows:
f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.
Given A, B, and n, you are to calculate the value of f(n).
f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.
Given A, B, and n, you are to calculate the value of f(n).
Input
The input consists of multiple test cases. Each test case contains 3 integers A, B and n on a single line (1 <= A, B <= 1000, 1 <= n <= 100,000,000). Three zeros signal the end of input and this test case is not to be processed.
Output
For each test case, print the value of f(n) on a single line.
Sample Input
1 1 31 2 100 0 0
Sample Output
25#include<stdio.h>int main(){ int a,b,n,i,arr[48]; while(~scanf("%d%d%d",&a,&b,&n),a||b||n) { arr[1]=1;arr[2]=1; for(i=3;i<48;i++) { arr[i]=(a*arr[i-1]+b*arr[i-2])%7; } printf("%d\n",arr[n%48]); }}
0 0
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