560. Subarray Sum Equals K
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Description:
Given an array of integers and an integer k, you need to find the total number of continuous subarrays whose sum equals to k.
Solution:
- 暴力列举所有可能的子连续序列和
- 计算前n个序列的和,并储存与map中,再根据nums[0:i] - nums[0:j]的值来计算nums[j:i]的和
class Solution(object): def subarraySum(self, nums, k): sums, cnt, dict1 = 0, 0, {0:1} for i in nums: sums += i if dict1.get(sums - k) != None: cnt += dict1[sums - k] dict1[sums] = 1 if dict1.get(sums) == None else dict1[sums] + 1 return cnt
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- 560. Subarray Sum Equals K
- 560. Subarray Sum Equals K
- 560. Subarray Sum Equals K
- 560. Subarray Sum Equals K
- 560. Subarray Sum Equals K
- 560. Subarray Sum Equals K
- 560. Subarray Sum Equals K
- 560. Subarray Sum Equals K
- Subarray Sum Equals K
- Subarray Sum Equals K
- Subarray Sum Equals K
- Subarray Sum Equals K
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