leetcode-candy

Candy

There are N children standing in a line. Each child is assigned a rating value.
You are giving candies to these children subjected to the following requirements:
Each child must have at least one candy. Children with a higher rating get more candies than their neighbors. What is the minimum candies you must give?

解题思路：
1、从左到右扫描，如果右边比左边分数高，右边在左边糖果数基础上+1，否则糖果数为1
2、从右边到左扫描，如果左边分数比右边大，且左边糖果树不小于或等于右边糖果数，那么左边糖果数在右边糖果数基础上+1
3、最后求糖果数总和

public class Solution {    public int candy(int[] ratings) {        if(ratings.length==1)            return 1;       int[] candy=new int[ratings.length];        candy[0]=1;//        for(int i=1;i<ratings.length;i++){            if(ratings[i-1]<ratings[i]){//如果右边比左边分数大，就糖果数加1               candy[i]=candy[i-1]+1;             }else{                candy[i]=1;//否则糖果数为1            }        }         for(int i=ratings.length-2;i>=0;i--){            if(ratings[i]>ratings[i+1]&&candy[i]<=candy[i+1]){               candy[i]=candy[i+1]+1;                       }       }        int sum=0;        for(int i=0;i<ratings.length;i++){            sum+=candy[i];        }        return sum;    } }