1001. 害死人不偿命的(3n+1)猜想 (15)

#include<stdio.h>int main(){  int x=0,i=0;  scanf("%d",&x);  if(x<=0)    return 0;      while(x!=1)  {    if(x%2==0)      x=x/2;    else      x=(3*x+1)/2;    i++;  }  printf("%d",i);  return 0;}