1054. 求平均值 (20)

来源：互联网发布：华为p7手机壳淘宝编辑：程序博客网时间：2024/06/03 17:33
#include<iostream>#include<cstdlib>#include<cstdio>#include<cstring>using namespace std;int main(){    char *num[105];    int N,count=0;    double average=0;    cin>>N;    for(int i=0;i<N;i++){        bool isNumber=true;     //判断是否为合法数字        int point=0;            //监视小数点的个数        int point_=0;           //监视小数点之后的位数        num[i] = (char *)malloc(10*sizeof(char)); //申请空间        cin>>num[i];        int len=strlen(num[i]);        double temp=atof(num[i]);//将字符串转换成数字，具体用法自行百度        if(temp<-1000||temp>1000)   isNumber=false;        for(int j=0;j<len;j++){  //对每一个元素的各个字符进行判断            if(point==1) point_++;              if(num[i][j]=='-'&&j!=0){//如果含有-，则-只有一个且在第一位                isNumber=false;                break;            }            if(num[i][j]!='.'){                     if((num[i][j]<'0'||num[i][j]>'9')&&(num[i][j]!='-')){                    isNumber=false;                    break;                }                   }else {             //如果是小数点                point++;            }            if(point_>2||point>1){//如果小数点大于一个或者小数位数多余2                isNumber=false;                break;            }        }        if(!isNumber)            cout<<"ERROR: "<<num[i]<<" is not a legal number"<<endl;        else {            count++;            average+=temp;        }    }    if(count==1)        printf("The average of 1 number is %.2lf",average);    else if(count==0)        printf("The average of 0 numbers is Undefined");    else        printf("The average of %d numbers is %.2lf",count,average/count);    return 0;}
0 0