Investment(POJ-2063 && HDU-1963)
来源:互联网 发布:口语救生圈怎么样知乎 编辑:程序博客网 时间:2024/06/16 18:56
Description
John never knew he had a grand-uncle, until he received the notary's letter. He learned that his late grand-uncle had gathered a lot of money, somewhere in South-America, and that John was the only inheritor.
John did not need that much money for the moment. But he realized that it would be a good idea to store this capital in a safe place, and have it grow until he decided to retire. The bank convinced him that a certain kind of bond was interesting for him.
This kind of bond has a fixed value, and gives a fixed amount of yearly interest, payed to the owner at the end of each year. The bond has no fixed term. Bonds are available in different sizes. The larger ones usually give a better interest. Soon John realized that the optimal set of bonds to buy was not trivial to figure out. Moreover, after a few years his capital would have grown, and the schedule had to be re-evaluated.
Assume the following bonds are available:
ValueAnnual
interest4000
3000400
250
With a capital of e10 000 one could buy two bonds of $4 000, giving a yearly interest of $800. Buying two bonds of $3 000, and one of $4 000 is a better idea, as it gives a yearly interest of $900. After two years the capital has grown to $11 800, and it makes sense to sell a $3 000 one and buy a $4 000 one, so the annual interest grows to $1 050. This is where this story grows unlikely: the bank does not charge for buying and selling bonds. Next year the total sum is $12 850, which allows for three times $4 000, giving a yearly interest of $1 200.
Here is your problem: given an amount to begin with, a number of years, and a set of bonds with their values and interests, find out how big the amount may grow in the given period, using the best schedule for buying and selling bonds.
John did not need that much money for the moment. But he realized that it would be a good idea to store this capital in a safe place, and have it grow until he decided to retire. The bank convinced him that a certain kind of bond was interesting for him.
This kind of bond has a fixed value, and gives a fixed amount of yearly interest, payed to the owner at the end of each year. The bond has no fixed term. Bonds are available in different sizes. The larger ones usually give a better interest. Soon John realized that the optimal set of bonds to buy was not trivial to figure out. Moreover, after a few years his capital would have grown, and the schedule had to be re-evaluated.
Assume the following bonds are available:
interest4000
3000400
250
With a capital of e10 000 one could buy two bonds of $4 000, giving a yearly interest of $800. Buying two bonds of $3 000, and one of $4 000 is a better idea, as it gives a yearly interest of $900. After two years the capital has grown to $11 800, and it makes sense to sell a $3 000 one and buy a $4 000 one, so the annual interest grows to $1 050. This is where this story grows unlikely: the bank does not charge for buying and selling bonds. Next year the total sum is $12 850, which allows for three times $4 000, giving a yearly interest of $1 200.
Here is your problem: given an amount to begin with, a number of years, and a set of bonds with their values and interests, find out how big the amount may grow in the given period, using the best schedule for buying and selling bonds.
Input
The first line contains a single positive integer N which is the number of test cases. The test cases follow.
The first line of a test case contains two positive integers: the amount to start with (at most $1 000 000), and the number of years the capital may grow (at most 40).
The following line contains a single number: the number d (1 <= d <= 10) of available bonds.
The next d lines each contain the description of a bond. The description of a bond consists of two positive integers: the value of the bond, and the yearly interest for that bond. The value of a bond is always a multiple of $1 000. The interest of a bond is never more than 10% of its value.
The first line of a test case contains two positive integers: the amount to start with (at most $1 000 000), and the number of years the capital may grow (at most 40).
The following line contains a single number: the number d (1 <= d <= 10) of available bonds.
The next d lines each contain the description of a bond. The description of a bond consists of two positive integers: the value of the bond, and the yearly interest for that bond. The value of a bond is always a multiple of $1 000. The interest of a bond is never more than 10% of its value.
Output
For each test case, output – on a separate line – the capital at the end of the period, after an optimal schedule of buying and selling.
Sample Input
110000 424000 4003000 250
Sample Output
14050
题意:银行买债券,拿利息,债券是可以卖的,n年后钱最多;
ps:这个题不知道为啥一直Runtime Error ,直到把dp大小改成 dp[200000]才对了
没看懂题,最大利率是10%,最多存40年,本金最大1000000,所以最后最大为450多万;
#include<stdio.h>#include<string.h>#include <algorithm>using namespace std;int dp[200000];int main(){int t;scanf("%d",&t);while(t--){int sum,k,m,n;scanf("%d%d",&sum,&n);int d;int i,j,a[15],b[15];scanf("%d",&d);for(i=0;i<d;i++){scanf("%d%d",&a[i],&b[i]);a[i]=a[i]/1000;}m=sum;for(k=0;k<n;k++){m=sum;m=m/1000;memset(dp,0,sizeof(dp));for(i=0;i<d;i++){for(j=a[i];j<=m;j++){dp[j]=max(dp[j],dp[j-a[i]]+b[i]);}}sum+=dp[m];}printf("%d\n",sum);}return 0;}
阅读全文
0 0
- Investment(POJ-2063 && HDU-1963)
- hdu 1963 poj 2063 Investment(完全背包)
- POJ 2063 Investment (完全背包)
- POJ 2063 Investment DP(完全背包)
- poj 2063 Investment(dp背包)
- poj 2063 Investment(背包问题)
- POJ 2063 Investment(完全背包)
- poj 2063 Investment 题解(背包)
- POJ 2063 Investment(完全背包)
- POJ 2063Investment(完全背包)
- POJ 2063 - Investment(完全背包)
- POJ 2063 Investment(完全背包)
- POJ 2063 Investment (完全背包)
- POJ 2063 Investment(完全背包问题)
- POJ 2063 Investment(完全背包)
- poj 2063 Investment(完全背包)
- poj 2063 Investment
- POJ 2063 Investment
- hjr教程-PHP(四):xampp与laravel框架
- 程序猿学习第六天,CSS
- C++中 export关键字的使用
- 对序列化的认识
- 关于DWR的使用方面
- Investment(POJ-2063 && HDU-1963)
- CentOS、Ubuntu、Debian三个linux比较异同
- 在Android上实现SPI通信之(1)------在Ubuntu12.04环境下编译android源码
- PHP AJAX 实现跨域保存数据的问题
- Excel转sql
- jQuery Mobile 弹窗
- JNI简介
- STM32读取MQ4传感器、DHT11温湿度传感器、GP2Y1014AU0F夏普光学灰尘传感器数据
- MaterialDesign之SearchView全面解锁