链表反转算法-java实现

来源:互联网 发布:吊带袜天使 知乎 编辑:程序博客网 时间:2024/06/08 10:24
public class Test{    public static void main(String[] args){        //初始化链表        Node head = new Node(0);        Node node1 = new Node(1);        Node node2 = new Node(2);        Node node3 = new Node(3);            head.setNext(node1);        node1.setNext(node2);        node2.setNext(node3);                //打印链表        Node n = head;        while(n != null){            System.out.print(n.getData + "  ");            n = n.getNext();        }                //反转链表        Node headRe = reverseNode(head);                //打印反转链表        Node m = headRe;        while(m != null){            System.out.print(m.getData + "  ");            m = m.getNext();        }    }    public static Node reverseNode(Node head){        if(head == null) return;        Node pre = head;//标记为上一个结点        Node cur = head.getNext();//当前结点        Node tem = null;//下一个结点        while(cur != null){            tem = cur.getNext();            cur.setNext(pre);//反转操作                        //指针下移            pre = cur;            cur = tem;        }        //最后将原链表的头节点的指针域置为null        head.setNext(null);            return pre;    }}
public class Node(){    private int data;  //链表结点数据      private Node next; //链表结点指针    public Node(int data){        this.data = data;    }    public Node getNext(){        return next    }        public void setNext(Node next){        this.next = next;    }        public int getData(){        return data;    }        public void setData(int data){        this.data = data;    }}
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