1001. 害死人不偿命的(3n+1)猜想 (15)

#include<stdio.h>int main(){  int n,count=0;  scanf("%d",&n);  while(n!=1){    if(n%2==1) n=(3*n+1)/2;    else n=n/2;    count++;  }  printf("%d",count);    return 0;}