codeforces 472A Design Tutorial: Learn from Math

网址：点击打开链接

A. Design Tutorial: Learn from Math

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

input

12

output

4 8

input

15

output

6 9

input

23

output

8 15

input

1000000

output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.

题意：求两个数的和等于n，并且这两个数都不是质数，结果有多组的话，输出其中一组。

#include<stdio.h>#include<math.h>int prime(int x){    int w=floor(sqrt(x)+0.5);    for(int j=2; j<=w; j++)    {        if(x%j==0)            return 0;    }    return 1;}int main(){    int n;    scanf("%d",&n);    for(int i=4; i<n; i++)    {        if((prime(i)==0)&&(prime(n-i)==0))        {            printf("%d %d\n",i,n-i);            break;        }    }    return 0;}