Codeforces 812A Sagheer and Crossroads[模拟]

题意：（这题关键就是理解题意了。。） 

1. p[i]为1的时候，如果当前方向也有1，是会发生事故的，

2. p[i]为1的时候，其他方向开向 i 的路上也有1，也会发生事故。

以下是代码：

int l[5], s[5], r[5], p[5];int main() {for (int i = 1; i <= 4; ++i) {scanf("%d%d%d%d", &l[i], &s[i], &r[i], &p[i]);}bool flag = 0;for (int i = 1; i <= 4; ++i) {if (p[i] == 1 && (l[i] == 1 || s[i] == 1 || r[i] == 1))flag = 1;}if (p[1] == 1 && (l[2] == 1 || s[3] == 1 || r[4] == 1))flag = 1;if (p[2] == 1 && (r[1] == 1 || l[3] == 1 || s[4] == 1))flag = 1;if (p[3] == 1 && (r[2] == 1 || l[4] == 1 || s[1] == 1))flag = 1;if (p[4] == 1 && (l[1] == 1 || s[2] == 1 || r[3] == 1))flag = 1;if (flag)printf("YES\n");else printf("NO\n");}