hdu 2044 斐波那契

题目地址：点击打开链接

#include<stdio.h>main(){  int i,M,N,a,b;  double feibo[51];  feibo[1]=1;  feibo[2]=1;  for(i=3;i<=51;i++){    feibo[i]=feibo[i-1]+feibo[i-2];  }  scanf("%d",&N);  for(i=0;i<N;i++){    scanf("%d%d",&a,&b);    M=b-a;    printf("%.f\n",feibo[M+1]);  }}