(二叉查找树)LeetCode#96. Unique Binary Search Trees
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- 题目:给定一个整数n,表示一个二叉树的节点个数为n,节点值从1到n,求这些节点能够构成的二叉查找树的总数
- 难度:Medium
- 思路:
- 代码:
public class Solution { public int numTrees(int n) { if(n <= 0){ return 0; } if(n == 1){ return 1; } int[] result = new int[n+1]; result[0] = 1; result[1] = 1; for(int i=2; i <= n; i ++){ for(int j = 1; j <= i; j++){ result[i] += result[j-1]*result[i-j]; } } return result[n]; }}
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