423. Reconstruct Original Digits from English
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class Solution(object):
def originalDigits(self, s):
"""
:type s: str
:rtype: str
"""
ss=collections.Counter(s)
tmp=['z','o','w','t','u','f','x','s','g','i']
i=0
ans=''
while i<len(tmp):
if i%2==0 and tmp[i] in ss:
for j in range(ss[tmp[i]]):
ans+="%s"%i
elif i%2==1 and tmp[i] in ss:
if tmp[i]=='o':
n=ss[tmp[i]]-ss[tmp[0]]-ss[tmp[2]]-ss[tmp[4]]
elif tmp[i]=='t':
n=ss[tmp[i]]-ss[tmp[2]]-ss[tmp[8]]
elif tmp[i]=='f':
n=ss[tmp[i]]-ss[tmp[4]]
elif tmp[i]=='s':
n=ss[tmp[i]]-ss[tmp[6]]
elif tmp[i]=='i':
n=ss[tmp[i]]-ss[tmp[6]]-ss[tmp[8]]-ss['f']+ss[tmp[4]]
for j in range(n):
ans+="%s"%i
i+=1
def originalDigits(self, s):
"""
:type s: str
:rtype: str
"""
ss=collections.Counter(s)
tmp=['z','o','w','t','u','f','x','s','g','i']
i=0
ans=''
while i<len(tmp):
if i%2==0 and tmp[i] in ss:
for j in range(ss[tmp[i]]):
ans+="%s"%i
elif i%2==1 and tmp[i] in ss:
if tmp[i]=='o':
n=ss[tmp[i]]-ss[tmp[0]]-ss[tmp[2]]-ss[tmp[4]]
elif tmp[i]=='t':
n=ss[tmp[i]]-ss[tmp[2]]-ss[tmp[8]]
elif tmp[i]=='f':
n=ss[tmp[i]]-ss[tmp[4]]
elif tmp[i]=='s':
n=ss[tmp[i]]-ss[tmp[6]]
elif tmp[i]=='i':
n=ss[tmp[i]]-ss[tmp[6]]-ss[tmp[8]]-ss['f']+ss[tmp[4]]
for j in range(n):
ans+="%s"%i
i+=1
return ans
0,2,4,6,8分别由z,w,u,x,g确定
1,3,5,7,9分别由o,t,f,s,i:
13579的个数算法分别为减去后边的个数:
1--》0,2,4
3--》2,8
5--》4
7--》6
9--》6,8,5
由于5不能直接确定,所以在算9的时候要通过f个数减去4的个数算
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