leetcode561. Array Partition I

来源:互联网 发布:网络幼儿英语 编辑:程序博客网 时间:2024/06/08 10:00

561. Array Partition I

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), …, (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1:

Input: [1,4,3,2]Output: 4Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4).

Note:
n is a positive integer, which is in the range of [1, 10000].
All the integers in the array will be in the range of [-10000, 10000].

解法

public class Solution {    public int arrayPairSum(int[] nums) {        Arrays.sort(nums);        int ret = 0;        for (int i = 0; i < nums.length; i = i + 2) {            ret += nums[i];        }        return ret;    }}
原创粉丝点击