1052. 卖个萌 (20)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

8000 B

判题程序

Standard

作者

CHEN, Yue

萌萌哒表情符号通常由“手”、“眼”、“口”三个主要部分组成。简单起见，我们假设一个表情符号是按下列格式输出的：

[左手]([左眼][口][右眼])[右手]

现给出可选用的符号集合，请你按用户的要求输出表情。

输入格式：

输入首先在前三行顺序对应给出手、眼、口的可选符号集。每个符号括在一对方括号[]内。题目保证每个集合都至少有一个符号，并不超过10个符号；每个符号包含1到4个非空字符。

之后一行给出一个正整数K，为用户请求的个数。随后K行，每行给出一个用户的符号选择，顺序为左手、左眼、口、右眼、右手——这里只给出符号在相应集合中的序号（从1开始），数字间以空格分隔。

输出格式：

对每个用户请求，在一行中输出生成的表情。若用户选择的序号不存在，则输出“Are you kidding me? @\/@”。

输入样例：

[╮][╭][o][~\][/~]  [<][>] [╯][╰][^][-][=][>][<][@][⊙][Д][▽][_][ε][^]  ...41 1 2 2 26 8 1 5 53 3 4 3 32 10 3 9 3

输出样例：

╮(╯▽╰)╭<(@Д=)/~o(^ε^)oAre you kidding me? @\/@

自己写的下面这个代码,感觉什么问题都没有,但是只有一个测例可以通过,代码如下:

/*************************************************************************> File Name: 1052.c> Author: YueBo> Mail: [e-mail]> Created Time: Sat 17 Jun 2017 11:12:01 PM CST ************************************************************************/#include <stdio.h>#include <string.h>#include <stdlib.h>#include <memory.h>int main(){    char zifu[3][64] = {0};    int index[3][64] = {0};    int user[1024][5];    int sz[3] = {0};    int K;    int i, j, k;    int val;    char buffer[128] = {0};    int idx[5] = {0,1,2,1,0};    int flag;    for (i = 0; i < 3; i++)    {        gets(zifu[i]);    }        for (i = 0; i < 3; i++)    {        j = 0;        k = 0;        while (zifu[i][j] != '\0')        {            if (zifu[i][j] == '[')            {                index[i][k] = j;                k++;            }            if (zifu[i][j] == ']')            {                zifu[i][j] = 0;            }            j++;         }        sz[i] = k;    }/*    for (i = 0; i < 3; i++)    {        for (j = 0; j < sz[i]; j++)        {            printf("%s", &zifu[i][index[i][j]+1]);        }        printf("\n");    }*/    scanf("%d", &K);    for (i = 0; i < K; i++)    {        for (j = 0; j < 5; j++)        {            scanf("%d", &user[i][j]);        }    }    for (i = 0; i < K; i++)    {        flag = 0;        memset(buffer, 0, 128);        for (j = 0; j < 5; j++)        {            val = user[i][j];            if (val > sz[idx[j]])            {                flag = 1;                printf("Are you kidding me? @\\/@");                break;            }            strcat(buffer, &zifu[idx[j]][index[idx[j]][val-1]+1]);            strcat(buffer, j == 0 ? "(" : "");            strcat(buffer, j == 3 ? ")" : "");        }        printf("%s", flag == 0 ? buffer : "");        printf("\n");    }    return 0;}

下面这段代码和自己的思想差不多,只不过博主把内容解析出来单独存了起来,原文参见http://blog.csdn.net/chr1991/article/details/51014817

从下面这个代码中得到的启发是,一个任务要进行适当的分解,一步一步的解决,不要一下子把几步的事情一下了了,这样的代码看起来很简洁,但是自己写的时候困难(调的时候困难),别人理解起来困难,分成一步一步的,不要耍快耍酷,怎么清楚明白怎么来.

具体到本题就是:

第1步:把眼,口,手,表情包分别解析出来,存到单独的内存中;

第2步:根据用户请求直接把表情调出来;

#include <stdio.h>  #define MAX 5  #define MAX_CH 10  void read_expression(char array[][MAX], int* count);  int main(int argc, const char * argv[]) {      char hand[MAX_CH][MAX], eye[MAX_CH][MAX], month[MAX_CH][MAX];      int k, hand1, eye1, month1, eye2, hand2;      int i, hand_count = 0, eye_count = 0, month_count = 0;      read_expression(hand, &hand_count);      read_expression(eye, &eye_count);      read_expression(month, &month_count);      scanf("%d", &k);      for( i = 0; i < k; i++){          scanf("%d %d %d %d %d", &hand1, &eye1, &month1, &eye2, &hand2);          if(hand1 <1 || hand1 > hand_count || hand2 < 1 || hand2 > hand_count){              printf("Are you kidding me? @\\/@\n");              continue;          }          if(eye1 <1 || eye1 > eye_count || eye2 < 1 || eye2 > eye_count){              printf("Are you kidding me? @\\/@\n");              continue;          }          if(month1 < 1 || month1 > month_count){              printf("Are you kidding me? @\\/@\n");              continue;          }          printf("%s(%s%s%s)%s\n", hand[hand1 - 1], eye[eye1 - 1], month[month1 - 1], eye[eye2 - 1], hand[hand2 - 1]);      }      return 0;  }  void read_expression(char array[][MAX], int* count){      int i, j, flag;      char temp;      i = 0;      j = 0;      flag = 0;      while((temp = getchar()) != '\n'){          if(temp == '[' && !flag){              j = 0;              flag = 1;          }          else if( temp == ']' && flag){              array[i][j] = '\0';              i++;              flag = 0;          }          else if(flag){              array[i][j++] = temp;          }      }      *count = i;  }  #include <stdio.h>  #define MAX 5  #define MAX_CH 10  void read_expression(char array[][MAX], int* count);  int main(int argc, const char * argv[]) {      char hand[MAX_CH][MAX], eye[MAX_CH][MAX], month[MAX_CH][MAX];      int k, hand1, eye1, month1, eye2, hand2;      int i, hand_count = 0, eye_count = 0, month_count = 0;      read_expression(hand, &hand_count);      read_expression(eye, &eye_count);      read_expression(month, &month_count);      scanf("%d", &k);      for( i = 0; i < k; i++){          scanf("%d %d %d %d %d", &hand1, &eye1, &month1, &eye2, &hand2);          if(hand1 <1 || hand1 > hand_count || hand2 < 1 || hand2 > hand_count){              printf("Are you kidding me? @\\/@\n");              continue;          }          if(eye1 <1 || eye1 > eye_count || eye2 < 1 || eye2 > eye_count){              printf("Are you kidding me? @\\/@\n");              continue;          }          if(month1 < 1 || month1 > month_count){              printf("Are you kidding me? @\\/@\n");              continue;          }          printf("%s(%s%s%s)%s\n", hand[hand1 - 1], eye[eye1 - 1], month[month1 - 1], eye[eye2 - 1], hand[hand2 - 1]);      }      return 0;  }  void read_expression(char array[][MAX], int* count){      int i, j, flag;      char temp;      i = 0;      j = 0;      flag = 0;      while((temp = getchar()) != '\n'){          if(temp == '[' && !flag){              j = 0;              flag = 1;          }          else if( temp == ']' && flag){              array[i][j] = '\0';              i++;              flag = 0;          }          else if(flag){              array[i][j++] = temp;          }      }      *count = i;  }  

/*************************************************************************> File Name: 1052_1.c> Author: YueBo> Mail: [e-mail]> Created Time: Tue 20 Jun 2017 08:42:52 PM CST ************************************************************************/#include <stdio.h>#include <stdlib.h>void read_expression(char array[][16], int* count){        char ch;        int i = 0;        int j = 0;        while((ch = getchar()) != '\n'){            if(ch == '['){                i++;            j = 0;            }            else if( ch == ']'){                array[i-1][j] = '\0';                j = 0;        }            else{                array[i-1][j] = ch;                j++;        }        }        *count = i;    } int GetExpression(char arr[][16]){    char ch = 0;    int cnt = 0;    int loopi = 0;    while ((ch = getchar()) != '\n')    {        if (ch == '[')        {            cnt++;            loopi = 0;            continue;        }        else if (ch == ']')        {            arr[cnt-1][loopi] = '\0';            loopi = 0;        }        else        {            arr[cnt-1][loopi] = ch;            loopi++;        }    }    return cnt;}int main(){    char hands[16][16];    char eyes[16][16];    char mouse[16][16];    int cnt;    int loopi;//    cnt = GetExpression(hands);    read_expression(hands, &cnt);    for (loopi = 0; loopi < cnt; loopi++)    {        int i = 0;        while (hands[loopi][i] != '\0')        {            printf("%c", hands[loopi][i]);            i++;        }    }    printf("\n");    return 0;}