PHP文件上传接口(带参数)

来源:互联网 发布:jquery数组push对象 编辑:程序博客网 时间:2024/06/06 03:56

简单讲解下PHP服务端接受客户端上传的文件
客户端上传文件到服务器,带参数,并且进行用户验证,方法很简单

直接贴代码

<?php    //强制显示错误    error_reporting(E_ALL);    // error_reporting = E_ALL & ~E_NOTICE    ini_set('display_errors', '1');    $UserId = str_replace("'", "", $_REQUEST["UserId"]);//接收用户ID    $Token = str_replace("'", "", $_REQUEST["Token"]);//接收Token    $sql = "SELECT * FROM `im_user` WHERE `UserId` = '$UserId'";    $request = mysql_fetch_assoc(mysql_query($sql));    //进行验证,如果验证通过,处理接收文件    if (md5($UserId.$request["UserToken"]."qwertyuiop") == $Token)     {            //判断是否有文件上传        if (isset($_FILES['file'])) {            //定义文件            $name = time().rand(10000000,99999999);            $target_path  = "./uploadfile/";//接收文件目录            // echo $target_path.$name.$_FILES['file']['type'];             // $target_path = $target_path.basename($_FILES['file']['name']);            $target_path = $target_path.basename($name.".FT");            //将文件从临时目录拷贝到指定目录            if(move_uploaded_file($_FILES['file']['tmp_name'], $target_path)) {                //上传成功,可进行进一步操作,将路径写入数据库等.                echo "The file ".basename( $_FILES['file']['name']). " has been uploaded";            }  else{                     echo "There was an error uploading the file, please try again!" . $_FILES['file']['error'];            }            exit;        }else        {            echo "没有文件";        }    }else    {        echo "认证不通过!";    }?>