Leetcode：207. Course Schedule

代码：

class Solution {

public:
    bool canFinish(int numCourses, vector<pair<int, int>>& prerequisites) {
        vector<unordered_set<int>> graph = make_graph(numCourses, prerequisites);
        vector<bool> onpath(numCourses, false), visited(numCourses, false);
        for (int i = 0; i < numCourses; i++)
            if (!visited[i] && dfs_cycle(graph, i, onpath, visited))
                return false;
        return true;
    }
private:
    vector<unordered_set<int>> make_graph(int numCourses, vector<pair<int, int>>& prerequisites) {
        vector<unordered_set<int>> graph(numCourses);
        for (auto pre : prerequisites)
            graph[pre.second].insert(pre.first);
        return graph;
    } 
    bool dfs_cycle(vector<unordered_set<int>>& graph, int node, vector<bool>& onpath, vector<bool>& visited) {
        if (visited[node]) return false;
        onpath[node] = visited[node] = true; 
        for (int neigh : graph[node])
            if (onpath[neigh] || dfs_cycle(graph, neigh, onpath, visited))
                return true;
        return onpath[node] = false;
    }

};

思路：

对图进行一次深度优先搜索，如果存在某个点通过搜素可以搜索到该点本身，则证明图中存在环，否则就是有向无环图