codeforces 236A（Boy or Girl） Java

深夜水题，秒一波！！！

import java.io.BufferedReader;import java.io.BufferedWriter;import java.io.IOException;import java.io.InputStreamReader;import java.io.OutputStreamWriter;import java.io.PrintWriter;import java.io.StreamTokenizer;/** * 题意：去掉字符串中重复的字符，如果去重之后的字符串长度为偶数，则输出“CHAT WITH HER!”，否则输出“IGNORE HIM!” * * @author TinyDolphin *         2017/6/24 22:45. */public class Main {    /**     * 字符串去除重复字符的方法     */    public static String distinct(String str){        String distinctLetters; //去重之后的字符串        distinctLetters = str.charAt(0) + "";        char temp;        for (int index = 0; index < str.length(); index++) {            temp = str.charAt(index);            if (!distinctLetters.contains(temp + "")) {                distinctLetters += temp;            }        }        return distinctLetters;    }    public static void main(String[] args) throws IOException {        StreamTokenizer in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));        PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));        String letters;         //输入的字母        while (in.nextToken() != StreamTokenizer.TT_EOF) {            letters = in.sval;            out.println(distinct(letters).length()%2==0?"CHAT WITH HER!":"IGNORE HIM!");        }        out.flush();    }}