C语言 百钱百鸡 鸡兔同笼

任务描述

①编程实现：百钱买百鸡

公鸡5文钱一只，母鸡3文钱一只，小鸡3只一文钱，

用100文钱买一百只鸡,其中公鸡，母鸡，小鸡都必须要有，问公鸡，母鸡，小鸡要买多少只刚好凑足100文钱。

②编程实现：鸡兔同笼

有若干只鸡和兔在同个笼子里，从上面数，有S个头；从下面数，有N只脚。求笼中各有几只鸡和几只兔？

#include <stdio.h>#include <stdlib.h>#define JI 100int moneychicken(){int gongji = 5;int muji = 3;int gong = 1, mu = 1, xiao = 1;for (gong = 1; gong < 21; gong++) {for (mu = 1; mu < 34; mu++) {if ((gong*gongji + mu*muji + (JI - gong - mu) / 3 == JI) && ((JI - gong - mu) % 3 == 0)) {printf("公鸡:%d 母鸡:%d 小鸡:%d\n", gong, mu, (100 - gong - mu));}}}}int rabbitAndChicken(int head, int foot){printf("鸡:%d, 兔:%d\n", head - ((foot - 2 * head) / 2), ((foot - 2 * head) / 2));}int main(){int head, foot;scanf("%d %d", &head, &foot);moneychicken();rabbitAndChicken(head, foot);return 0;}