基础语言-题目64(鸡兔同笼)

主要的就是一个解决问题的思路

#include <stdio.h>#include <string.h>#include <math.h>#include <iostream>#include <string>#include <algorithm>using namespace std;int main (){int N;cin >> N;while (N--){int num_elements, num_foot;cin >> num_elements >> num_foot;double ans_rabbit = ceil ( (num_foot - 2 * num_elements) / 2.0 ); //注意ceil返回值是double型,但是输出的确实整形 double ans_chicken = ceil ( (4 * num_elements - num_foot) / 2.0 );//cout << "ans_chicken = " << ans_chicken << " " << "ans_rabbit = " << ans_rabbit << endl; if (ans_chicken + ans_rabbit == num_elements && ans_rabbit >= 0 && ans_chicken >= 0){cout << ans_chicken << " " << ans_rabbit << endl;}else{cout << "No answer" << endl;}}return 0;}