位操作-leetcode 338 Counting Bits
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原题链接:Counting Bits
题解:
class Solution {public: vector<int> countBits(int num) { /* i的1的个数等于i>>1+i&1的,然而i>>1在已经计算出来 Time Complexity:O(N) Space Complexity:O(N) */ vector<int>ivec(num+1,0); for(int i=1;i<=num;i++){ ivec[i]=ivec[i>>1]+(i&1); } return ivec; }};
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