LeetCode #20 Valid Parentheses

Description

Given a string containing just the characters ‘(‘, ‘)’, ‘{‘, ‘}’, ‘[’ and ‘]’, determine if the input string is valid.

The brackets must close in the correct order, “()” and “()[]{}” are all valid but “(]” and “([)]” are not.

---

Analysis

题目难度为：Easy
括号匹配考查的是栈的出入栈问题——如果是左括号则入栈，如果是右括号，栈顶是相匹配的左括号则左括号出栈。当输入右括号，栈为空或者栈顶括号不匹配，则匹配出错。

---

Code（c++)

class Solution {public:    bool isValid(string s) {        stack<char> st;        for (int i = 0; i < s.size(); ++i) {            if (s[i] == '(' || s[i] == '[' || s[i] == '{') {                st.push(s[i]);            }            else if (s[i] == ')') {                if (!st.empty() && st.top() == '(') st.pop();                else return false;            }            else if (s[i] == ']') {                if (!st.empty() && st.top() == '[') st.pop();                else return false;            }            else if (s[i] == '}') {                if (!st.empty() && st.top() == '{') st.pop();                else return false;            }        }        if (st.empty()) return true;        return false;    }};